UVa- 11247 ( Income Tax Hazard Solution )

Try Yourself First. For help Scroll Down .

Tip : All you need to do is to find a formula for Effective Income of person . Here Effective Income  simply means the Minimum Amount you have to earn Which will be greater than ' M ' but after giving  tax it'll be less than ' M ' . If ' X ' is 100 then the result won't be evaluated. That means " No solution " will return. If not then find the income using the Formula you have . If the result is FRACTIONAL then hold here . If NOT then DECREASE the result by ' 1 '. Now check weather It's GREATER than ' M ' or Not . If GREATER than M then print it . If NOT then print " No solution ". 

!!! Warning : Use ' long long int ' . Don't use " double " data type . Move to Code now.

Code :

#include<bits/stdc++.h>

using namespace std;

int main()

{

    long long int m,income;

    int x;

    while(scanf("%lld %d",&m, &x)==2)

    {

        if(m==0 && x==0) break;

        if(x==100)

            printf("Not found\n");

        else

        {

            income = (m-1)*100/(100-x);

            if((m-1)*100%(100-x)==0)

                income = income - 1;

            if(income<m)

                printf("Not found\n");

            else

               printf("%lld\n",income);

        }

    }

    return 0;

}

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